support custom api url per model

This commit is contained in:
Dax Raad
2026-02-11 23:10:47 -05:00
parent 5bdf1c4b96
commit ad2087094d
2 changed files with 3 additions and 3 deletions

View File

@@ -64,7 +64,7 @@ export namespace ModelsDev {
status: z.enum(["alpha", "beta", "deprecated"]).optional(),
options: z.record(z.string(), z.any()),
headers: z.record(z.string(), z.string()).optional(),
provider: z.object({ npm: z.string() }).optional(),
provider: z.object({ npm: z.string(), api: z.string() }).optional(),
variants: z.record(z.string(), z.record(z.string(), z.any())).optional(),
})
export type Model = z.infer<typeof Model>

View File

@@ -629,7 +629,7 @@ export namespace Provider {
family: model.family,
api: {
id: model.id,
url: provider.api!,
url: model.provider?.api ?? provider.api!,
npm: model.provider?.npm ?? provider.npm ?? "@ai-sdk/openai-compatible",
},
status: model.status ?? "active",
@@ -781,7 +781,7 @@ export namespace Provider {
existingModel?.api.npm ??
modelsDev[providerID]?.npm ??
"@ai-sdk/openai-compatible",
url: provider?.api ?? existingModel?.api.url ?? modelsDev[providerID]?.api,
url: model.provider?.api ?? provider?.api ?? existingModel?.api.url ?? modelsDev[providerID]?.api,
},
status: model.status ?? existingModel?.status ?? "active",
name,